WebIf you use Java 7 it can be done in two lines thanks to the Files#readAllLines method: List lines = Files.readAllLines (yourFile, charset); String [] arr = lines.toArray (new String [lines.size ()]); Share Improve this answer Follow answered Oct 12, 2012 at 10:40 assylias 319k 78 658 776 Web5 Jan 2024 · Having created an array, you can take advantage of the array’s indexing and write a for loop, like this: for (int roomNum = 0; roomNum < 10; roomNum++) { guestsIn …
java - Store words in array - Stack Overflow
Web14 Feb 2011 · The application needs to store all +120,000 words. It needs to name them word_1, word_2, etc. And it also needs to access these words to perform various methods on them. The methods all have to do with Strings. For instance, a method will be called to say how many letters are in word_80. Web5 Jan 2024 · Having created an array, you can take advantage of the array’s indexing and write a for loop, like this: for (int roomNum = 0; roomNum < 10; roomNum++) { guestsIn [roomNum] = 1; } This loop takes the place of ten assignment statements because the computer executes the statement guestsIn [roomNum] = 1 ten times. off grid life book
Read File Into an Array in Java - GeeksforGeeks
Web12 Dec 2012 · simply loop thru the items in array like the one below and remove white space for (int i = 0; i < temp.length; i++) { temp [i] = if (!temp [i].trim ().equals ("") temp [i]!=null)temp [i].trim (); } Share Improve this answer Follow edited Dec 12, 2012 at 6:30 answered Dec 12, 2012 at 5:34 Murali N 3,381 4 27 38 Web14 Apr 2024 · Naming is hard, it always depends on context/domain. I suppose this is from a math problem/algorithm? In that case, it will depend on whether there are any x variables nearby that could lead to confusion, e.g. ax might be mistaken for "a * x", or for "x component of vector a". In case of doubt, use longer, more descriptive names rather than the … Web26 Jun 2015 · import java.util.Scanner; public class ReadAndStoreNames { public static void main (String [] args) throws Exception { Scanner scan = new Scanner (System.in); //take 10 string values from user System.out.println ("Enter 10 names: "); String n = scan.nextLine (); String [] names = {n}; //store the names in an array for (int i = 0; i < 10; i++) { … off grid land nh